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ok if you can help solve these last ones im good to go and i thank everyone for all their help
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\[\sqrt[3]{40x^3}=\sqrt[3]{2^3*5*x^3}=2x \sqrt[3]{5}\]is your answer there are several way to write answer by factor,I don't know which way, you want write,I try do this some \[2x(\sqrt[3]{5})\]or\[\sqrt[3]{5}(2x)\]
\[\sqrt{16x^2}=|4x|=4|x|\] \[(\sqrt{10}+5\sqrt{2})(\sqrt{10}+5\sqrt{2})=10-50=-40\]
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