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OpenStudy (anonymous):
Find the stationary points on the curve y=(3x-1)(x-2)^4 I differentiated it and brought it down to: 0=(x-2)^2(3(x-2)+4(3x-1)) yet i only got one correct x value (2), the other is (2/3) which i can't seem to get...
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OpenStudy (anonymous):
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