Question

Which is (sin B+ cos C) in the right triangle ABC, given AB = 20, AC = 48, and mA = 90?
and the answer has to be a fraction

Answer 1

Find hypotenuse first
\[BC=\sqrt{20^2+48^2}=52\]
sinB=AC/BC=48/52
cosC=AC/BC=48/52
sinB+cosC=48/52+48/52=24/13