Question

(4x ^3 + 7y ^3 z ^4) ^2

Answer 1

wait it says that wrong

Answer 2

ok gotcha

Answer 3

That's a binomial inside the parentheses...you need ot use FOIL

Answer 4

LA-MrC...that's incorrect

Answer 5

Let's try this again:

(4x ^3 + 7y ^3 z ^4) * (4x ^3 + 7y ^3 z ^4)

Answer 6

16x^6 + 56x^3y^3z^4 + 49y^6z^8

Answer 7

\[(4x^{3}+7y^{3}z^{4})^{2}=(4x^{3}+7y^{3}z^{4})(4x^{3}+7y^{3}z^{4})\]\[=16x^{(3+3)}+4(7)x^{3}y^{3}z^{4}+4(7)x^{3}y^{3}z^{4}+49x^{(3+3)}z^{(4+4)}\]\[=16x^{6}+56x^{3}y^{3}z^{4}+49y^{6}z^{8}\]