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(0.1x + 0.4y)^2
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0.1x * 0.1x + 0.1x*0.4y + 0.1x*0.4y+ 0.4y* 0.4y
im still confused
\[=(\frac{x}{10}+\frac{4y}{10})(\frac{x}{10}+\frac{4y}{10})\]So,\[\frac{x^2+8xy+16y^2}{100}\]If you want it in decimal form then,\[=0.01x^2+0.08xy+0.16y^2\]
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