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Mathematics 15 Online
OpenStudy (anonymous):

can anyone help me on my last question?

OpenStudy (anonymous):

whats your last q

OpenStudy (anonymous):

OpenStudy (anonymous):

m<ADB=14

OpenStudy (anonymous):

can you show me how you got that and show me how you get the rest of them please?

OpenStudy (anonymous):

m<ADB=180 m<A+m<ADB+m<ABD=180 90 + m<ADB + 76 =180 166 + m<ADB =180 m<ADB =180-166 m<ADB =14

OpenStudy (anonymous):

ok is that how you do all of them

OpenStudy (anonymous):

m<CDB+128=180B m<CDB=180-128 m<CDB=52 m<BCD+m<CDB+m<DBC=180 90 + 52 +m<DBC=180 142 + m<DBC=180 m<DBC=180-142 m<DBC=38

OpenStudy (anonymous):

m<B=76+38 m<B=114

OpenStudy (anonymous):

ok so how come you did not have to do all the things you did on the other ones for this one

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

I do,which one need to do first

OpenStudy (anonymous):

m<b

OpenStudy (anonymous):

I have to find m<CDB first

OpenStudy (anonymous):

well chris angle B wud b 114,but the missing angle is 38

OpenStudy (anonymous):

than next find m<CDB than add ; m<CBD+m<ABD=m<b

OpenStudy (anonymous):

KBOY can u finish the rest,I have to go ty

OpenStudy (anonymous):

uhmmmm hello?

OpenStudy (anonymous):

chris buddy. u hav answer to q2?

OpenStudy (anonymous):

how do i figure it out im clueless right now

OpenStudy (anonymous):

well there are three angles in the triangle. u hav the value of two and you need to find the third. sum of angles of a triangle =180

OpenStudy (anonymous):

so 180 = angle A + 76 + ADB, and we knw that angle A is 90, so 180=90+76+ADB..solve for ADB now

OpenStudy (anonymous):

14

OpenStudy (anonymous):

yup. q3 we worked out already when we did q1

OpenStudy (anonymous):

so the answer 2 number 2 is 14

OpenStudy (anonymous):

yeah. and the answer to q3 is 180-128, we already worked this owt wen we did q1

OpenStudy (anonymous):

ok so whats next?

OpenStudy (anonymous):

are you familiar with pythagoras?

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

sorry my mom made me do something and no

OpenStudy (anonymous):

ok. the theorem says that the square of the hypotenuse is equal to the sum of the squares on the other two sides. the hypotenuse is the length of the side opposite the 90degree angle

OpenStudy (anonymous):

so what is the hypotenuse in triangle BDC

OpenStudy (anonymous):

90?

OpenStudy (anonymous):

the hypotenuse is the side opposite the 90degree angle. the hypotenuse is 16

OpenStudy (anonymous):

ok ima give you the answers coz i gta go. 4. CD= sqrt(175)

OpenStudy (anonymous):

5. sin(76)= AD/16...AD=16sin(76)

OpenStudy (anonymous):

6. BA=16sin(14)

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