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Help? Please simplify: 2-x/3 ----- 5+x/8
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\[=\frac{6-x}{3} / \frac{40+x}{8}\] \[=\frac{(6-x)}{3} * \frac{8}{(40+x)}\] \[=\frac{8(6-x)}{3(40+x)}\]
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