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find the area between the curve y=abs. vale of lnx and the x-axis, and lines x=e and x=1/e
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its that hard?
\[\int_{\frac{1}{e}}^1 -\log (x) \, dx+\int_1^e \log (x) \, dx\]
why negative log?
the change?
because log[x] is negative between 1/e and 1, we want positive
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ohhhh
so what is the integral of - log x?
i dont know how to do it thou
Try graphing you will see
i did.....
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but how do i do the integral?
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