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OpenStudy (anonymous):
-1/(2x+1) or
(-1/2x)+1?
OpenStudy (anonymous):
7
14
18 these are the only possible awnser
OpenStudy (anonymous):
and 1 over 2
OpenStudy (anonymous):
No post the proper question! There's a difference use parenthesis!
OpenStudy (anonymous):
its multiply choice... so i t has to be one of those.
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OpenStudy (anonymous):
1 =-x+8
----
2x+1
1=(2x+1)(-x+8)
1=-2x^2+16x-x+8
1=-2x^2+15x+8
1-8=-2x^2+15x
-7=-2x^2+15x
-2x^2+15x=-7
-2x^2+15x+7=0
please do check my signs
OpenStudy (anonymous):
i still have no awnser...
OpenStudy (anonymous):
-1/(2x+1) = -x+8
-1 = -x+8(2x+1)
-1 = -2x^2-x+16x+8
-1+8 = 2x^2+15x
7 = x(2x+15)
7/x = 2x+15
(7-15)/x = 2x
-8/x = 2x
-8 = 2x^2
x^2 = -8/2
x = root of -4
x = -2
but i am not sure about this
OpenStudy (anonymous):
-1 over 2 x + 1 = −x + 8
No wait i think he meant:
(-1/2)x+1 = -x+8
(1/2)x+1 = 8
x+2= 16
x = 14
OpenStudy (anonymous):
THANKYOU
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