A charged particle m=8E-10kg q= 5E-15c is accelerated through a potential difference of 300 volts and projected into a region where magnetic field is 300T. If particle is projected perpendicular to magnetic field, describe the trajectory of the particle. Find the radius of the orbit.

Question

anonymous · Answer

the gain in energy is qV = 5 x 10^(-15)C * 300V (units are Joules). 
Fmagnetic = qvB sin(90)
get the v from 1/2 mv^2 = qV
plug into the formula above to get Fmagnetic... this force must be equal to mv^2/r
Solve for r

anonymous · Answer

thank you soo much!