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here the problem im working on i got my answers to be 77/4..but its wrong...please helphttp://www.webassign.net/cgi-bin/symimage.cgi?expr=int_%28-2%29%5E%283%29%20%5C%28x%5E3-2%20x%5C%29%20dx
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(x^4/4)-2x^2/2) \[\left(\begin{matrix}3 \\ -2\end{matrix}\right)\]
I got 45/4... ?
and i got up to (3^4/4 -9) - (-2)^4/4- (-2)^2
how?
=x^4/4-x^2=81/4 -9 - (4-4)=(81-36)/4=45/4
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o i see you know what i did i change the signs to positive....thanks a lot
:)
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