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OpenStudy (anonymous):
Choose the correct simplification of the expression (xyz2)4. x5y5z6 x5y5z8 xyz16 x4y4z8 Yes they are to the the powers.
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OpenStudy (anonymous):
4
OpenStudy (anonymous):
\[(xyz^2)^4 = (x)^4(y)^4(z^2)^4 = x^4y^4z^{2*4} = x^4y^4z^8\]
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