Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Calculus integral question...2nd last one for today:

OpenStudy (anonymous):

OpenStudy (anonymous):

HERE WE GO!!

OpenStudy (anonymous):

I AM AN INTEGRAL! lolz anyway.. velocity is the integral of acceleration..

OpenStudy (anonymous):

lmaoooo yes sir, that you are.

OpenStudy (anonymous):

Int ( 2t+4 ) = t^2 + 4t + C

OpenStudy (anonymous):

Sorry got an urgent call from the derivative.. soo

OpenStudy (anonymous):

V(0) = -5 -5 = 0 + 0 +C => C = -5 V(t) = t^2 + 4t - 5

OpenStudy (anonymous):

Total distance d traveled.. again set V = 0 t^2 + 4t - 5 = 0, t=-5, t=1

OpenStudy (anonymous):

So split the integral at 1 since -5 is not in the interval..

OpenStudy (anonymous):

Yes, part one is correct. and lmaooooooooooo!!! got an urgent call from the derivative hahahaha

OpenStudy (anonymous):

Int (t^2 + 4t - 5,t,0,1) = -8/3 Int (t^2 + 4t - 5,t,1,3) = 44/3

OpenStudy (anonymous):

take abs values and add: (44+8)/3 = 52/3 = 17.333

OpenStudy (anonymous):

was that right?

OpenStudy (zarkon):

yes

OpenStudy (anonymous):

Yessir. :)

OpenStudy (anonymous):

xD I IZ ZE TRUE INTEGRAL.. Dang it should've called myself integrand sign haha

OpenStudy (anonymous):

hahaha wow

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!