Question

hello-- how do i do (3^-2)^(5/2)
please i want to learn how to do it thanks
God bless you all

Answer 1

\[(3^{-2})^{5/2}\]?

Answer 2

3^-2 = 1/9
(1/9)^5/2 = radical(1/9)^5 =(1/9)^2radical(1/9)=1/81 (radical(1/9) =
=(1/81)(1/3)=1/3^5

Answer 3

=3^(-5)