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solve the equation: log3 X+log3 (x-24)=4 p;ease show me step by step
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base 3 ?
yes
\[\log _{3}x+\log _{3}(x-24)=4\]
right?
yes
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\[x(x-24)=3^4\]can u solve from now?
oh.. ok.. thanks i see its now:)...
\[x^2-24x-81=0\]
(x+3)(x-27)=0
x=-3 x=27 x=27 is solution
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and i so confuse about.. why dont we take the -3???
just the formula,look on the lesson loggarithms can't not negative
ok thanks:)....
or you can plug x=-3 and x=27 and check
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