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(5A (with T on top) ) to the power of -1 = -3 -1 5 2 find A
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basically its the inverse of transpose of A x 5 gives that 2x2 matrix
I hope this is right, I haven't done this in quite a while... Take the inverse again to undo the inverse on the other side, which gives you--> \[\left[\begin{matrix}-2 & -1 \\ 5 & 3\end{matrix}\right]\] Take the transpose of this to undo the transpose on the other side and divide by 5--> \[\left[\begin{matrix}-2/5 & 1 \\ -1/5 & 3/5\end{matrix}\right]\]
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