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give the exact and approximate solutions to three decimal places (x-3)^2 =16
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\[x-3=\sqrt{16}\]x=4+3 x=7
it says 7 is one answer its asking for two im confused
they always ask for two..
I for got \[x-3=\pm \sqrt{16}\]\[x=3\pm4\]
they do?
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x=7 or x= -1
ok i think
ill post another one can you shw me step by step so i can try
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