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2/5, 9/10, 7/5, 19/10, 12/5 Find the common difference between the terms of the following arithmetic sequence.
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\[1\div5\]
\[\frac{12}{5}=a _{1}+(n-1)d\]
Common Difference of an A.P = Second term - First term = Third term - Second term = ... = k
Here Common difference = (9/10) - (2/5) = 1/2
\[\frac{12}{5}=\frac{2}{5}+(5-1)d\]\[\frac{12}{5}-\frac{2}{5}=4d\]\[\frac{10}{5}=4d\]\[d=\frac{\frac{10}{5}}{4}\]\[d=\frac{10}{5}*\frac{1}{4}\]\[d=\frac{1}{2}\]
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