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Find the common ratio of the geometric sequence: 1.2, 0.84, 0.588, 0.4116
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Common ratio = .84 /1.2 = 7/10
or 0.4116/0.588= 7/10
Common Ratio is always a constant. common ratio will give the same result in any case second term / first term,third term /second term ,fourth term/third term .....
0.4116=1.2*r^(4-1) 0.4116/1.2 =r^3\[r=\sqrt[3]{0.343}=0.7\]
No need to apply tn = a r^(1-n) r you can get directly as i said
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many way to solve
I know this is offtopic, but is this advanced geometry or calculus 2?
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