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solve for m s=4m-3n/21
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s = 4m-3n/21 please first clear my doubt is it s =(4m-3n)/21 or s = 4m - (3n/21)
21s=4m-3n 21s+3n=4m m=21s+3n/(4)
the first one
Can anyone tell me about the minimum value of m?
i did right it is all right no mistake has been done !!
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i am confused because i am getting a different answer
ok see here (4m-3n)/21 = s 4m-3n = 21s 4m = 21s + 3n m = (21s + 3n)/4
this is what i got 7s+n/28
got it
No it would be 3(7s + n)/4
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