Question

http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_%28-2%29%5E0%20%5C%288%20u%2A%2A5%20-%208%20u%2A%2A3%20%2B%203%20u%2A%2A2%5C%29%20du

Answer 1

i had that answer but its wrong?

Answer 2

whats the answer?

Answer 3

it an hybrid course...i dont really know

Answer 4

wait wait i knw

Answer 5

but do you know how to evaluate this interval http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_0%5E9%204%20sqrt%2817%20t%29%20dt

Answer 6

is the answer for the first one -184/3?

Answer 7

nope thats the answer they like i dont know why tho? but could you help me with the other question

Answer 8

the t is under the sqrt?

Answer 9

yes

Answer 10

then its integral of 4 sqrt7 *sqrt t
sqrt of t = t^1/2

so 4 sqrt of 7 is a constant

so ur left with 4 sqrt 7* integration t^1/2
which is 4 sqrt 7 t^3/2 all divided by 3/2
u get 8/3 sqrt 7 t^3/2
then just substitute 9 in t
u get 72 sqrt 7

Answer 11

ok cool i got that too thanks!

Answer 12

:D