Question

A rectangle has a length that is twice as long as its width and a perimeter of 36. What is its area?

Answer 1

\[2l+2w=36\]
\[2\times 2w+2w=36\]
\[6w=36\]
\[w=6\]

Answer 2

area is length times width. width is 6, length is 12

Answer 3

let the lenght b '2x' n width be 'x'
2(2x+x) = 36
2(3x) = 36
6x = 36
x = 36/6
x = 6
so,width = 6 n lenght = 2*6=12
area = l * b = 12 * 6 = 72

Answer 4

`2121