Question

In the following figure, NDBA is a rectangle, AN = NG, BF = DB, GD = 11, and DF = 8√2. What is the area of parallelogram GDFA?

Answer 1

DB=FB
in tri DBF,
DF^2=DB^2+FB^2
(8√2)^2 = DB^2+DB^2(DB=FB)
128 = 2DB^2
64 = DB^2
√64 = DB
DB = 8

Area of llgm = b*h
= GD*DB
= 11*8
= 88