Question

Put the equation in the form ax^2+bx+c=0.
(2x+1)^2-3x=5

Answer 1

\[4x^2+4x+1-3x=5\]
\[4x^2+x-4=0\]

Answer 2

man you love these.

\[(2x+1)^2-3x=5\]
\[(2x+1)(2x+1)-3x=5\]
\[4x^2+4x+1-3x=5\]
\[4x^2+x+1=5\]
\[4x^2+x-4=0\]

Answer 3

NOOOO I hate these!