Question

Consider the quadratic relation y = x2 - 2x - 35.

Use the three different algebraic methods you have learned to rewrite the relation in vertex form.

Answer 1

here is the easy one.
take
\[\frac{-b}{2a}\] and the write
\[y=a(x+\frac{b}{2a})^2+f(\frac{-b}{2a})\]

Answer 2

so in this case you would put
\[y=(x-1)^2+ \text{whatever you get when x = 1}\]

Answer 3

The second way is to complete the square

Answer 4

and the third?

Answer 5

i dunno i missed that class. what did the teacher say?

Answer 6

lmfao.. i wasnt in that class..

Answer 7

factoring and finding line of symetary.
x^2-2x-35
(x-7)(x+5)
We know that solution is 7 and -5 and line of symmetary should be in middle
7-5/2 =1
x=1

plug in 1 into equation
(x-1)^2 + whatever you get when you plug in x=1