could someone explain how to factor this quadratic equation
\[25m ^{2}-30m+9\]
sure... I'll guide you and u pls give ans to my questions/suggestions.
general form of quadratic equation is ax² + bx + c first find the product of a and c for your equation..
225
very good !!! now find a pair of factors of 225 whose sum is 30..
25 and 5
like 1 * 225 = 225 3 * 75 = 225 5 * 45 = 225 .......... ..........
25 * 5 = 125 and not 225 !!
i know i wasnt paying attention, i cant find it
15 * 15 = 225
yeah i just saw that
now our bx term is -30x so we have to ensure that the product of these two factors is 225 and their sum is -30 how can we do that???
make the factors of 255 negative
brilliant !!! -15 * -15 = 225 and (-15) + (-15) = -30
so the answer is (x-15)(x-15)?
no, it is not like this... pls follow further instructions...
ok
so we can rewrite your quadratic polynomial as (it is not an equation because it is not = to something) 25m² - 30m + 9 25m² - 15m - 15m + 9 now make pairs of first two terms and last two terms.... then for each pair take out the common factor and enclose the leftover in brackets.. (e.g. 15x² + 3x = 3x(5x + 1)
i dont undedrstand that
ok... first take 25m² - 15m what is their GCF ????
5
no it is 5m so take 5m out and put leftover in bracket 5m( ........)
so its 5m(5m-15m)5m(3m+9)?
i dont think thats right though
No, u hv made a mistake.... 25m² - 30m + 9 25m² - 15m - 15m + 9 5m(5m - 3) -3(5m -3) <------ the terms in the bracket have to be same !!! do you get this???
oh ok thanks alot
so final factors are (5m -3)(5m-3) if u r satisfied with the help, pls click GOOD ANSWER button for me....☺☻☺
how would i do\[9x ^{2}+42x+49\]? I got up to \[9x ^{2}+21x+21x+49\] but they dont have a GCF
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