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Mathematics 20 Online
OpenStudy (anonymous):

how would I factor 9x^2+42x+49? I got up to 9x2+21x+21x+49 but 9 and 49 dont have a GCF

OpenStudy (anonymous):

3x

OpenStudy (anonymous):

Break the 9x^2 into (3x+a)(3x+b)

OpenStudy (anonymous):

u hv to take GCF of first two terms and last two terms..

OpenStudy (anonymous):

9x²+42x+49? 9x²+21x+21x+49 ------- ------- 3x(3x + 7) +7 (3x + 7)

OpenStudy (anonymous):

got it???

OpenStudy (anonymous):

9x2+21x+21x+49 bracket off [9x2+21x]+[21x+49] factorise each bracket 3x[3x+7] + 7[3x + 7] Hence factors are [3x + 7]^2

OpenStudy (anonymous):

where do you get 49 from 3x(3x + 7) +7 (3x + 7)

OpenStudy (anonymous):

7*7

OpenStudy (anonymous):

wow...i feel stupid

OpenStudy (anonymous):

no problem..... as long as u r trying hard to learn...☺

OpenStudy (anonymous):

ok thanks

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