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how would I factor 9x^2+42x+49? I got up to 9x2+21x+21x+49 but 9 and 49 dont have a GCF
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3x
Break the 9x^2 into (3x+a)(3x+b)
u hv to take GCF of first two terms and last two terms..
9x²+42x+49? 9x²+21x+21x+49 ------- ------- 3x(3x + 7) +7 (3x + 7)
got it???
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9x2+21x+21x+49 bracket off [9x2+21x]+[21x+49] factorise each bracket 3x[3x+7] + 7[3x + 7] Hence factors are [3x + 7]^2
where do you get 49 from 3x(3x + 7) +7 (3x + 7)
7*7
wow...i feel stupid
no problem..... as long as u r trying hard to learn...☺
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