Question

(x+8)(x-13)(x+5)>0
{xI_} if there is a solution
is the solution all real numbers
or is there no solution?

Answer 1

jst use the number line to find the solution
solve for x
(x+8)(x-13)(x+5)=0
x=-8, x=13, x=-5 and then choose test points

Answer 2

So there wold be no solution?

Answer 3

There is a solution, but it is limited to an interval. It isn't all real numbers though

Answer 4

---|----|----|----
-8 -5 13

choose a number before -8 like -9 and plug it into (x+8)(x-13)(x+5)

choose a number between -8 and -5 like -6 and plug it into (x+8)(x-13)(x+5)

choose a number between -5 and 13 like 0 and plug it into (x+8)(x-13)(x+5)

choose a number after 13 like 14 and plug it into (x+8)(x-13)(x+5)

Answer 5

(-9+8)(-9-13)(-9+5)=(-1)(-22)(-4)=negative number<0

(-6+8)(-6-13)(-6+5)=(2)(-19)(-1)=positive number>0

(0+8)(0-13)(0+5)=(8)(-13)(5)=negative number<0

(14+8)(14-13)(14+5)=(22)(1)(19)=positive number>0

Answer 6

so which intervals >0 ?