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triple integral (cylindrical) 0 to 2pi, 0 to 3, 0 to Z/3 of r^3 dr dz dtheta; I have did this several times but I cannot get the answer of 3pi/10 some one catch my mistake?
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"some one catch my mistake?" show what you have done and I'll point out any errors
int 0 to z/3 of r^3 dr= 1/4r^4 evaluated from 0 to z/3 = z^4/324 correct?
yes
int 0 to 3 of z^4/324=1/5z^5 evaluated from 0 to 3 (1/324 the constant)=243/324 or 3/4 correct?
I get 3/20
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1/5 z^5 (1/324) yes?
yes
crap....i forgot to multiply by 1/5
yep
nice catch thanks
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np
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