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OpenStudy (agentjamesbond007):
How do you factor 2√x + 6x^3/2 = 2√x ( ?#? )
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OpenStudy (anonymous):
\[2x^{1/2}+6x^{3/2}\]
OpenStudy (anonymous):
\[2x^{1/2}(1+3x)\]
OpenStudy (anonymous):
2 root x cancels and leaves u with 3x^3 = 1 which has a root 1/cube root 3 and 2 complex roots.
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