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20x^3y^2z/48x^4yz^2
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(5y)/(12xz)
First, reduce the fraction 20/48 to get 5/12. Now divide x^3 into x^4 to get \[\frac{x^3}{x^4}=\frac{1}{x}\] Now divide y^2 into y to get \[\frac{y^2}{y}=y\] Finally, divide z into z^2 to get \[\frac{z}{z^2}=\frac{1}{z}\] Now put everything together to get the answer \[\frac{5y}{12xz}\]
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