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simplify and state the excluded values for each variable #1 3x^2-10x+3/3x^2-7x+2 #2 z^2+z-12/z^2-z-12
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\[\frac{3x^2-10x+3}{3x^2-7x+2}\]?
wait up the first one is the exact same thing i just wrote isnt ot?
qstion is fine
simplify it to get (3x-1)(x-3)/(3x-1)(x-2) = x-3/x-2
excluded value x=2
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\[\frac{(3x-1)(x-3)}{(3x-1)(x-2)}=\frac{x-3}{x-2}\]
x=2 you need number 2 ?
the excluded value for x is 2 coz 2-2 =0 which makes the fraction infinite
next one answer is (z+4)(z-3) / (z-4)(z+3)
in this excluded values for z are -3, 4
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Yeah nancy I need help with #2
roopadr give u answer
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