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pls. help me simplifying this: y-1/(2y-1)y-1
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\[\frac{y-1}{(2y-1)(y-1)}\]?
the y-1 in numerator and denominator will cancel out
if so get \[\frac{1}{2y-1}\] but i am not sure that is what you meant.
\[\frac{y-1}{(y-1)(2y-1)}\] the y-1 cancels on top and bottom because they are like factors (y-1)/(y-1) = 1 \[\frac{y-1}{(y-1)(2y-1)}= \frac{1}{2y-1} \]
\[y-1/(2y-1)y-1 \]
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thats the equation
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