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At what y points on the curve xy = 25 is the tangent line parallel to 5x + y = 0?
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when its slope is -a/b given the form ax + by = c
the derivative of xy=25 wrt x is: y + xy' = 0; y' = -y/x = -5/1
need some x,y in xy that comes at to 25 and slopes to -5/1
or something like that :)
plus minus sqrt 5?
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we could look at this as y = 25/x to get y' = -25/x^2 = -5
to wit estudier gives good advise
-25/x^2 = -5
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