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(How Much Water must be added to 20 liters of 50% alcohol solution to Dilute it to 10%)
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a + b = t ; *-x xa + yb = zt -xa -xb =-xt xa+yb = zt ------------ b(y-x)= t(z-x) b@y = t(z-x)/(y-x) maybe
water@0 = 20(.50 - .10)/(0-.10); chop off the negative and se if it works :)
i get 80, maybe 80(0) + 20(.50) ?= 100(.10) 0 + 10 ?= 10 yep
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