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k^2+4k=96
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think of two numbers which are factors of -96 and when added give +4
(k+12)(k-8)
how about -12 and 8 ot 12 and -8?
nerd has it 12 and -8
-12 and 8 because k+12 = 0 k=-12 and k-8=0 k=8
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no -12 and 8 give -4
k^2+4k=96 k^2+4k-96=0 (k+12)(k-8)=0 -------- k+12=0 k=-12 --------- k-8=0 k=8 --------- possible answers are: -12 and 8 discard negatives and answer is: "8"
so?
fill it in k^2+4k=96 8^2+4(8) = 96 yes!?
yes - i see now - we are at cross purposes - the roots are -12 and 8 - when i referred to 12 and -8 I was talking about the numbers which go into the brackets - the numbers which give -96 and +4
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ok. so we agree on the answer, right?
yep
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