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Mathematics 20 Online
OpenStudy (anonymous):

for the function defined by f(x)={x^2 x<=1} {2x+1 x>1} evaluate f(0) and identify the function that will be used when x=0

OpenStudy (anonymous):

Since x = 0 and 0 <= 1 then we use x^2 to evaluate the function here. 0^2 = 0, so f(0) = 0

OpenStudy (anonymous):

so for the answer i just put 0?

OpenStudy (anonymous):

f(0) = 0 using x^2

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