Question

4u^2/u^2-36 divided by -2u/u^2+8u+12

Answer 1

((4u^2) * (u^2 + 8u +12)) / ((u^2 -36) * (-2u))

Answer 2

\[\frac{4u^2}{u^2-36} / \frac{-2u}{u^2+8u+12}\]
\[=\frac{4u^2}{(u+6)(u-6)} * \frac{(u+6)(u+2)}{-2u}\]
\[=\frac{-2u(u+2)}{(u-6)}\]