Question

If g(x)=(x-1)^2, what is g(t+at)

Answer 1

\[g(t+\Delta t)\]

Answer 2

g(t+at)=g(t+at-1)^2

Answer 3

\[g(x)=x^2-2x+1\]
\[g(x+\Delta x)=(x+\Delta x)^2+(x+\Delta x)+1\] then some algebra

Answer 4

\[g(x+Delta x)=x^2+2x\Delta x+(\Delta x)^2+x+\Delta x +1\]

Answer 5

g(t+at)=t^2+2at^2+a^2t^2-2at-2t