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find the equation of a line passing through (-4,3) and (1,2)
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First find slope
m=(2-3)/(1+4)=-1/5
ok first thing u find the slope 2-3/1+4 -1/5 then u choose any of the points u have ill choose (1,2) to find the y-intercept y=mx+b 2=-1/5(1)+b , 2=-1/5+b , 10/5+1/5 =b , 11/5 =b the equation of the line is y=-1/5 +11/5
y=-1/5x +11/5 **
Now use \[y-y _{1}=m(x-x _{1})\]
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