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OpenStudy (anonymous):
Solve system: y = x^2 - 3x y = 2x - 6
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OpenStudy (anonymous):
set them equals to each other x^2-3x = 2x -6
OpenStudy (anonymous):
How do I solve?
OpenStudy (anonymous):
add 3x to both side
OpenStudy (anonymous):
x^2-5x+6=0 x^2-3x-2x+6=0 x(x-3)-2(x-3)=0 (x-2)(x-3)=0 So x=2,3
OpenStudy (anonymous):
What about y....?
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