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A right triangle in the first quadrant is bounded by lines y = 0, y = x, and y = -x+5. Find its area.
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Solve equations y=x and y=-x+5 at first
u will get (5/2,5/2)
So the vertices of triangle are (0,0),(5/2,5/2) and (5,0) I hope u can do it from now on
Thanks Roshan
My pleasure as always............
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There is another way of solving the problem as well if u study the graph carefully
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