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i have any question,6(12 ^2+5^2)^0 can you help this question?
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answer is 6 anything to the power 0 is 1 so 6*1 = 6
how about this question (4^2+3^2)^-1
Any number [except 0] which is raised to the power 0 is equal to 1 Therefore 6 x 1 = 6 is the result.
1/25
(4^2+3^2)^-1 =[16 +9]^-1 = 25^-1 0 1/25
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how about this question 5\p^6
5p^-6
how about this question 5\(a+b)^3
You can only expand the denominator, but I do not see the point in that.
anyway it is 5/a^3 +a^2b +ab^2 +b^3
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sorry 5/a^3 +2a^2b +2ab^2 +b^3
sorry,the question is 5/(a+b)^3
so it is the answer?
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