Question

The perimeter of a rectangular lot is 56 meters. The length exceeds the width by 12 meters. Find the length of the lot.
14 m
28 m
15 m
20 m

Answer 1

l=12+w
perimeter=2(l+w)=56
2(l+l-12)=56
2l=40
l=20

Answer 2

l=20m

Answer 3

see here it is given that length = 12 + width that is l =12 + w
now see here
as we know that the perimeter of a rectangle = 2(l+w)
we have
56 m = 2(12+w+w)
56 m = 2(12+2w)
28m = 12 + 2w
28 - 12m = 2w
16m = 2w
16m/2 =w
8m = width
and l = 12 + w that is l = 12 + 8 = 20m hence
l = 20m
and
b = 8 m