Question

xsq +3x-18=0

Answer 1

You have to factor this Sonya

So:
x ^2 - 3x - 18 = 0
(x^2 + 6x) (-3x - 18) = 0
x( x + 6) -3 (x + 6)

(x - 3) (x + 6 )
Set them both equal to 0 and find your x values

Answer 2

So
x - 3 = 0

and

x+ 6 = 0