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OpenStudy (anonymous):
Solve for x, and write the exact answer using base-10 logarithms. 2^(9x)=16^(-x+9)
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OpenStudy (anonymous):
2^(9x)=(2^4)^(-x+9) 2^(9x)=2^(-4x+36) 9x=-4x+36 13x=36 x=36/13
OpenStudy (anonymous):
what does this have to do with base ten logarithms? or any logarithms?
OpenStudy (anonymous):
i dont know, thats why i'm asking!
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