A point is moving along the graph of a given function such that dx/dt is 2 centimeters per second. Find dy/dt for the given values of x. y = 9x2 + 5 (a) x = -1 dy/dt =____ cm/sec (b) x = 0 dy/dt =____cm/sec (c) x = 3 dy/dt =_____ cm/sec
\[y'=18xx'\] and you are told that \[x'=0\] so you get \[y'=36x\] just plug in the numbers
sorry i mean you are told that \[x'=2\]
this one is mile easier than the first ones. i wonder why they get easier.
I have is the question I am trying to take my ASVAB test and this question I do not get at all 4! that is all the information they give
4!
what?
@navyman are you asking about \[4!\] did you get lost in this post? am i hallucinating?
so satletite what would the numbers be like hwat am i plugging in
@lostdove all you have to so is write \[\frac{dy}{dt}=36x\] and so first one is \[36\times -1=-36\] second one is \[36\times 0=0\] third one is \[36\times 3=108\] easy an done
thanks:)
yw
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