Question

implify. fourthroot(a^6) - (2a)(sqrt a). click to see better format

Answer 1

\[\sqrt[4]{?x^6}-2x \sqrt{x}\]

Answer 2

oops. \[\sqrt[4]{x^6}-2x \sqrt{x}\]

Answer 3

\[\sqrt[4]{a}^{6}=a ^{6\times1/4}\]
\[a ^{3\div2}-2a \sqrt{a}\]
\[\sqrt[2]{a}^{3}-2a \sqrt{a}\]

Answer 4

isnt it 4 x 1/6

Answer 5

instead of 6 x 1/4

Answer 6

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Answer 7

well, i can help..
But im not very good with these.
but still, i can help!

Answer 8

thanks so much. ok. so you dont know this one?

Answer 9

i can do this.

Answer 10

yeah its pretty hard. umm how about..

Answer 11

\[(2/x)-(2/(2x+1))=1/x+1\]

Answer 12

find x ^^^

Answer 13

brb.

Answer 14

5mins!

Answer 15

k

Answer 16

it would be WAY easier if i opened up a classroom. cuz i got like 10 problems. but either way is fine. im still getting help.

Answer 17

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Answer 18

im already teaching someone!
u may join!

Answer 19

what happened? you got kicked?

Answer 20

"isnt it 4 x 1/6"

No, here are the rules:

a^b * a^c = a^{b+c}
a^b/a^c =a^{b-c}
(a^b)^c = a^{bc}

You have x^6 and you want the fourth root of it ie the quarter power, so

(x^6)^(1/4) = x^(6*1/4) = x^(3/2)

The other term is 2x (think 2x^1) multiplied by the half power

2xx^(1/2) = 2x^(3/2) so finally u have

x^(3/2) - 2x^(3/2) = -x^(3/2) which you can check at Wolfram

http://www.wolframalpha.com/input/?i=%28x^6%29^%281%2F4%29+-+2x*sqrt%28x%29