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OpenStudy (anonymous):
perform the indicated operation: (a+3)^2/a-3 ÷ 5/(a^2-9)
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OpenStudy (zarkon):
\[\frac{(a+3)^3}{a-3}\frac{a^2-9}{5}\] \[=\frac{(a+3)^3}{a-3}\frac{(a-3)(a+3)}{5}\] \[=\frac{(a+3)^4}{5}\]
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