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Find the product. (2x-4)(x^2-3x+6)
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2x^3 - 4x^2 - 6X^2 + 12x +12x - 24 = 2x^3 -10x^2 + 24x -24
Oh, I see...
also just for the sake of finishing the problem: real roots => x = 2 complex => x = .5(3\[\pm\]i\[\sqrt{15}\])
@aredsani, How did you get 12x+12x?
Wait, I got it. Nevermind. lol
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well 2x*6 and the other one -4 * -3 x
Yeah, it took me a minute to see that. lol
lol :D
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